Subnetting Part-02

Question-11

Enter the smallest summary route which would include all of the given subnets. Please present your answer in slash notation (i.e. 10.1.1.0/8).

The correct answer is: 172.28.0.0/15

Remember to check where the bits of each address fall. Sometimes two /24s do not fit into a single /23, instead one sits in one /23 and the other sits in a following /23. For example, 192.168.1.0/24 and 192.168.2.0/24 do not fit into a single /23. The first is half of 192.168.0.0/23 and the second is half of 192.168.2.0/23.

Question-12

Using the diagram below, which of the following IP addresses would be valid to asign to interface Fa0/3? For your answer type out the IP address.

192.168.0.9

192.168.0.71

192.168.0.101

The correct answer is: 192.168.0.9

See which IP fits outside the currently existing subnets.

Question-13

What is the broadcast address of the network 172.21.8.32 ?? 255.255.252.0

The correct answer is: 172.21.11.255

The broadcast address is one less than the next network address. Count in block sizes. The block size is either 256 minus the netmask, or 232-slash.

Question-14

How many subnets are needed for the following topology?

The correct answer is: 8

A router divides broadcast domains. Unless otherwise stated, a port on a router can usually be thought of as a separate subnet.

Question-15

What is the maximum number of valid hosts one will have from the network 192.168.197.0 ?? 255.255.255.128

The correct answer is: 126

There are 2h-2 usable hosts in a network, where h is the number of hot bits.

Question-16

What is the last valid host on the network that 192.168.180.10/30 is a part of?

The correct answer is: 192.168.180.10

The last usable IP is one less than the broadcast. Find the next block, then subtract two from that.

Question-17

What is the Subnet Mask corresponding to a shorthand of /22?

The correct answer is: 255.255.252.0

Question-18

What is the slash notation for the subnet mask 255.248.0.0? (e.g. /24)

The correct answer is: /13

This will be 32-h where h is the number of host bits.

Question-19

The following shows a network with two subnets. A device on the network is misconfigured. Select the letter of the device which has a an invalid IP address. Your answer should simply be the letter of the deivce (i.e. A).

The correct answer is: B

Find the block size and make sure that all the IPs fall within that block size. Then check to make sure no broadcast and network addresses are being assigned to hosts. Remember, the usable hosts are those between the broadcast and the network addresses.

Question-20

Enter the smallest summary route which would include all of the given subnets. Please present your answer in slash notation (i.e. 10.1.1.0/8).

The correct answer is: 172.20.0.0/15

Remember to check where the bits of each address fall. Sometimes two /24s do not fit into a single /23, instead one sits in one /23 and the other sits in a following /23. For example, 192.168.1.0/24 and 192.168.2.0/24 do not fit into a single /23. The first is half of 192.168.0.0/23 and the second is half of 192.168.2.0/23.?

?? Download Your Subnetting Cheatsheet ??

Get quick access to all the essential subnetting information in one handy cheatsheet!

Primary Download Link: Click Here

Alternative Download Link: Click Here

"Subnetting is the art of breaking down large networks into efficient, manageable segments. The key to network mastery starts here."