Problem Solving: First element to occur k times
SHUBHAM CHOUDHURY
UGC-NET (Assistant Professor) Qualified | Working on Artificial Intelligence, Machine Learning, Deep Learning & LLMs | Teaching & Mentoring College Students
We'll discuss an efficient solution to the problem of finding the first element that occurs at least k times in an array. We'll analyze the problem, explain the provided solution, and discuss its time and space complexity.
Problem Overview:
Given an array of integers and an integer k, we need to find the first element in the array that occurs at least k times. If there's no such element, we return -1.
Solution Approach:
We can efficiently solve this problem using a hash map (unordered_map in C++). Here's the step-by-step explanation of the solution:
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Let's implement this solution in code:
#include <bits/stdc++.h>
using namespace std;
class Solution
{
public:
int firstElementKTime(int n, int k, int a[])
{
// Create an unordered map to store frequency of elements
unordered_map<int, int> mp;
// Iterate through the array
for (int i = 0; i < n; i++)
{
// Update the frequency of current element
mp[a[i]]++;
// Check if the frequency becomes equal to k
if (mp[a[i]] == k)
{
// Return the element if condition is met
return a[i];
}
}
// If no such element is found, return -1
return -1;
}
};
Time Complexity Analysis:
The time complexity of this solution is O(n) because we iterate through the array once to calculate the frequency of each element.
Space Complexity Analysis:
The space complexity of this solution is also O(n) because we use an unordered_map to store the frequency of elements in the array.
Conclusion:
We discussed an efficient solution to find the first element occurring at least k times in an array. By using a hash map to store the frequency of elements, we were able to achieve a time complexity of O(n). This solution is optimal and fulfills the requirements of the problem efficiently.