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Herein! I am?sharing information and a detailed description of how to create an adiabatic grounding system, along with some sample computations. Please be aware that the values used in the computations are only illustrative and may not accurately represent real-world situations. Let's move on:

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Gather all the information you require regarding the factory facility, such as the electrical system details, fault current levels, soil resistivity, and any local rules or specifications that may be relevant.

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Assume that 10,000 A is the maximum fault current level.

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Assume that the site's soil resistivity is 100 -m.

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We'll use a 2-meter-long mm-diameter copper-clad grounding rod for this illustration.

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Suppose the grounding conductor is made of copper. The fault current level and maximum permitted temperature rise should be taken into account when calculating the conductor size.

Assume that copper has a reference resistivity of 0.0175 -mm2/m and a maximum temperature rise of 30°C. Using the equation:

Fault current (A) / (K t t )T = Cross-sectional area (mm2)

Where:

Copper's resistivity correction factor, K, is considered to be 0.124 -mm2/m.

t stands for the fault's duration, which is 1 second.

T is the highest temperature rise that is permitted (30 °C).

10,000 A / 0.124 mm2/m/s/1 s/30°C = 455.66 mm2 is the cross-sectional area.

Pick a copper conductor with a surface area of 500 mm2 out of the range of typical conductor sizes.

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Based on the desired resistance-to-ground and the soil resistivity, the length of the grounding conductor should be chosen. We'll strive for a resistance-to-ground of 1 in this scenario.

Length (m) is equal to (R) / (2R).

Where:

The soil's resistivity is 100 ohms.

R is the desired ground resistance (1 ).

The grounding rod's radius is r (16 mm / 2 = 8 mm = 0.008 m).

length equals (100 m-m x 1) / (two m-m x 0.008 m) = 19,829 m

Therefore, the length of the grounding conductor should be roughly 19,829 meters.

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We won't cover the design of the grounding grid in this example, but if necessary, you can consult the relevant standards and recommendations to choose the best grid layout based on the fault current levels, soil resistivity, and available space.

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You can use the following formula to determine GPR:

I Zg = GPR (V)

Where:

I representee 10,000 A fault current.

The grounding impedance, Zg, is 0.1 ohms.

GPR = 10,000 A × 0.1 Ω = 1,000 V

One thousand volts is the calculated GPR.

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Beyond the purview of this reaction, additional calculations are required to evaluate step and touch potentials. To assess step and touch potential dangers under fault circumstances and build suitable mitigation measures, consult relevant norms, laws, and skilled specialists.

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Record the design of your grounding system.