8 bit BCD to ASCII-8085

8 bit BCD to ASCII-8085

Simplified through Visualization......

Here we will reverse engineer the hardware to understand how program works at hardware level

So now for converting a number from BCD to ASCII we will obviously need data so we will get the data from memory to accumulator...

Obviously for this we will have to fetch the instruction from memory,how we will do it ....



now this address will be sent to memory when ALE is 1
ACTUALLY THE DATA TRANSFER IS DONE IN BINARY FORMAT

So, finally we have learnt how instruction gets fetched inside a microprocessor now when the instruction is getting decoded the program counter is incremented and a new instruction is fetched.

So,other instructions of this program will be fetched in similar way...

WE HAVE SUCCESSFULLY BUILT THE LOGIC

Let us reverse engineer the ALU to understand how this works at hardware level

Now we have got the desired output we will store it in the memory

Timing control unit will generate write signal...

So,finally we have successfully achieved our one goal...

What about the other...

how will store 32 at 3051...

But...

now we have no original data i.e 23 in the processor

So,dont you think we have missed something crucial....

We missed moving the content of A into B...

So how we will achieve the above outcomes...

Before this AND operation we must have content in accumulator so

MOV A,B


Success After 4 RLC operation we have got 2 at LSB

Now add 30 to it

ADI 30H

store the content at 3051 H

STA 3051H

So, finally we did it

LDA 2050 	
MOV B, A 	
ANI 0F 	
ADI 30 	
STA 3050 	
MOV A, B 	
ANI F0 	
RLC 	
RLC 	
RLC 	
RLC 	
ADI 30 	
STA 3051 	
HLT 	        

Thank you so much

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