Digest Trend Pro的动态

Because of filter media variations, gas turbine filters differ substantially, and each design comes with associated cost trade-offs.

New NSK high-load-capacity tapered roller bearings selected for wind?turbines

New NSK high-load-capacity tapered roller bearings selected for wind?turbines

Great day for all !!! wishing always the best in your life !! ... now talking about special steam turbines, we can say that steam turbines with condensing capabilities extract more energy by expanding steam to sub-atmospheric pressures, maximizing efficiency and power output. However, they require complex cooling systems and condensers, leading to higher operating costs and increased water consumption, making them ideal for applications demanding high thermal efficiency, such as power generation plants. On the other hand, back-pressure (non-condensing) turbines operate by discharging steam at higher pressures, simplifying design and allowing steam reuse in industrial processes like heating or petrochemical steam networks. While less efficient in energy conversion, these turbines are more flexible, require less maintenance, and have lower installation costs. Advantages of condensing turbines: Higher thermal efficiency and power generation. Used in combined-cycle plants for optimal performance. Disadvantages: Complex systems with high maintenance costs. Increased cooling water demand, limiting use in arid regions. Advantages of back-pressure turbines: Simpler design with lower installation costs. Flexibility for applications where residual steam can be repurposed. Disadvantages: Lower overall energy conversion efficiency. Not suitable for maximizing power generation in closed cycles. These factors are crucial when selecting the appropriate technology for critical industries like oil, gas, petrochemicals, and power generation, where reliability and operational efficiency are essential to reducing costs and preventing unexpected shutdowns. See ore details in my website https://lnkd.in/gnr3utfU, check it below ...

Key Drivers for Thermal Energy Storage Technologies in Industry

https://lnkd.in/gt5dTpNp Sand particles are heated to charge the thermal battery to 1200°C. The heated sand is stored for up to several days in insulated industrial silos. The particles transfer heat to air through a novel pressurized fluidized-bed heat exchanger( Patented). Target LCoS : USD5c / kwh For the demonstration purpose, 100 kilowatts and 10 hours storage is planned to demonstrate the integration between the heat exchanger and the power generator. This will be just 17 meters tall. Instead of burning coal to run the thermal power block, the former coal plant sites can rstore sand heated by electricity from curtailed wind or daytime solar. The heat stored in the sand can then be converted back into electricity through the thermal power block and delivered to the grid for hours when needed, for example during periods of low solar or wind availability.

It′s all around heat heat heat... The thermal management of gas engines (CHP) is a crucial factor for the smooth operation of cogeneration units. Proper thermal management ensures efficient and reliable performance, optimizing the overall system's efficiency and longevity. #ThermalManagement #GasEngines #CHP #Cogeneration #Efficiency #Reliability #texaco #

WOW??WHAT A DEAL ON TWO PLANTS AND TURBINE GENERATOR ??Three units for sale-15,000kVa Plant.- 3 X 4MW=12MW- Kawasaki gas turbine generator L30A. -GE 810 MW CCGT POWER PLANT?LOW HOURS??? ?GE 810 MW CCGT POWER PLANT?? LOW HOURS - ?For Sale / Relocation?Price / Further details upon request Price.?USD.?150 Million Inspection : Can be arranged at short notice . ?Location : Asia? ?Kindly advise your technical queries if any Combined Cycle GTPP for immediate delivery with full OEM Warranty. Unique?offer, complete Power Plant,?fully erected but unused?810 (2 x 405)?MW, full preservation?and maintenance?as per OEM instructions. * ?Kawasaki gas turbine generator L30A. 34mw 60hz, 30mw 50hz. ２０２０，11000v? For sale Kawasaki Gas turbine generator? L30A . 2020 model? Fuel gas.? As it is still foundation in Japan.? Low hour meter.?? Present cycle 60hz 34mw, but can be?modified?to?50hz 30mw by seller ( extra cost)? ?Simple open cycle, two shaft type?5 576 rpm? Pressure ratio 24.5? Exhaust gas temp: 502 deg.c? LHV of fuel 35.9(MJ/Nm3).? Thermal efficiency 41.2%? Total LHV thermal efficiency 85.5%?? Alternator: Meidensha 2020? 37.945kva 60hz 1992a? 11000v?? Steam absorption chiller? Kawasaki 2020? Cooling capacity 2462kw? Cold water flow rate 423.4 m3/h? Steam inlet pressure 0.785mp? Price at USD13.7 millon fob Japan. (60hz) * ?3 X 4MW=12MW?Please take a look at the attached Power Plant Package and let me know what you think. Our purchase is 7.9 m USD in storage in the Middle East.??? Brief Technical and Specification Report 15,000kVa Plant Introduction The Plant equipment consists of Gas Turbines, Generators, Transformers, Boilers, Switch/Control panels and Auxiliary equipment. The plant is 12MW in total, the plant has 3 gas turbines with 4MW capacity in each (5000kVa). This is a Japanese 2018 brand-new, unused plant from a cancelled project. The plant is the current latest eco green model of Kawasaki which is very advantageous for the client due to its reliability and durability since it runs HFO/Diesel . Conclusion The plant is currently dismantled and sealed in the warehouse in Japan. The plant is sold as it is and logistics could be arranged at an F.O.B price. ??Please advise your interest in either facility. PHBLTD Group of Companies Quest Corporate Development ?Lewes, Delaware 19958 ?Office: 301.526.7400 e-mail:?[email protected] Skype: Philip.blankfeld [email protected] LinkedIn:?https://www.dhirubhai.net WhatsApp London, UK 191 Cranmer Ct?Suite 191 London, SW3 3HG Dubai, UAE London Suites #102 Al Jadaf, Al Wasl Sports Complex ????'Circa 1982' #demolition

Designing a *500 MW #steam #power plant* involves several key steps, primarily focused on #thermodynamic #cycles, fuel requirements, steam generation, and power transmission. Here is a *very short* overview with essential formulas: *1. Define #Power #Output* To meet the required power output of *500 MW*, we will calculate the required heat input and steam generation. P = E/t Where: - P = Power (500 MW) - E = Energy produced (in MWh) - t = Time (in hours) For a 500 MW plant running for 24 hours: E = 500 MW× 24 hours = 12,000 MWh *2. #Boiler #Heat Input Calculation* For a *thermal power plant*, the heat input required can be calculated using the *efficiency* of the system: Q = P/η Where: - Q = Heat energy required (in MW) - η = Efficiency of the power plant (typically 33% to 45%) For a plant with 40% efficiency: Q = 500 MW/0.40 = 1250 MW *3. #Fuel #Requirements* Fuel consumption depends on the *calorific value* of the fuel (e.g., coal, natural gas) and the *thermal efficiency*: Fuel Consumption = Q/Calorific Value×η If using coal with a calorific value of *24 MJ/kg* (or 6,666.67 kWh/kg), calculate the fuel consumption. *4. #Steam #Generation (#Rankine Cycle)* The steam required for the turbine is based on the *Rankine cycle* efficiency and steam flow rate: P = ?× (h_1 - h_2) Where: - ? = Mass flow rate of steam (kg/s) - h_1 = Enthalpy of steam entering the turbine (kJ/kg) - h_2 = Enthalpy of steam exiting the turbine (kJ/kg) For a 500 MW plant, calculate the steam flow rate based on turbine specifications. *5. #Turbine and #Generator #Sizing* The turbine must match the output power of the plant. The generator should be sized as: P_gen = Rated Power×Efficiency of Generator For a 500 MW generator, the output is calculated based on the generator's efficiency. *6. #Cooling #System Design* For thermal plants, the cooling system (e.g., *wet cooling tower*) condenses steam back into water. The cooling load can be estimated: Q_cooling = ?× (h_1 - h_2) Where: - ? = Mass flow rate of cooling water (kg/s) - h_1 and h_2 = Enthalpy values of water before and after cooling. *7. Transmission and Voltage Regulation* Design the transmission system to carry the generated power efficiently. Use transformers and voltage regulation: V = √(P_transmission/R_line× I) Where: - P_transmission = Power to be transmitted - R_line = Resistance of transmission line - I = Current